On 5-3-2015 15:57, Aziz Saleh wrote:
On Thu, Mar 5, 2015 at 9:49 AM, Pete Ford <pete@xxxxxxxxxxxxx> wrote:
On 05/03/15 14:42, Maciek Sokolewicz wrote:
On 5-3-2015 13:04, hadi wrote:
Hi,
I created function, but im getting error:
(PHP Fatal error: Call to undefined function rss1() in
C:\phptest\test9.php
on line 17)
The error explains it perfectly. You're calling a function which has not
been defined yet. So... define your function BEFORE you call it, not
AFTER calling it.
So
<?php
function rss1() { ... }
rss1();
instead of
<?php
rss1();
function rss1() { ... }
- Tul
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There is also the problem is that his function is being defined inside the
Exception block (as far as I can tell from the parentheses) which looks
weird...
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In PHP you can call any function regardless if its before or after, as long
as it is within the scope. In your case like Pete mentioned, your function
is in your Exception scope. You have 2 options:
1) Please the function outside of the try/catch statement.
2) If you need to keep it within, move it on top of your function call.
I know that, and you know that, but I also know Hadi wouldn't understand
this (as is pointed out in the hundreds of other extremely basic
questions posted earlier); so attempting to answer his question in the
easiest manner possible (undefined? define before using!) was what I was
trying to do. Trying to explain scope and runtime evaluation of function
definitions isn't something that he would understand (yet) anyway.
- Tul
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