On Wed, Sep 3, 2014 at 11:23 AM, Peter Ford <pete@xxxxxxxxxxxxx> wrote:
> I came across a bug in some of my code, where I do something like the
> following:
>
> $obj = new MyObject();
>
> foreach ($obj as $key=>$value)
>
> {
>
> echo $key;
>
> }
>
>
> Note that I don't use $value in the loop - I'm only doing processing based
> on the field name.
> Now my IDE flags this unused variable as a hint, so (on autopilot) I
> changed it to be
>
> $obj = new MyObject();
> foreach (array_keys($obj) as $key)
> {
> echo $key;
> }
>
> Which removes the hint, and looks like the right sort of thing.
> Of course this doesn't work: "array_keys() expects parameter 1 to be an
> array, object found".
>
> So what is the correct way to list the field names of an object?
>
> Cheers
> Pete
>
> --
> Peter Ford phone: 01580 893333 fax: 01580 893399
> Justcroft International Ltd.
> www.justcroft.com
> Justcroft House, High Street, Staplehurst, Kent TN12 0AH United Kingdom
> Registered in England and Wales: 2297906
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>
>
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>
You could use get_object_vars
http://php.net/manual/en/function.get-object-vars.php
So something like the following may work (not tested)
$obj = new MyObject();
foreach (array_keys(get_object_vars($obj)) as $key)
{
echo $key;
}
Regards,
Shaun
