Re: PHP Mystery

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And var_dump($result1) will post the contents of $result1 to the screen, which can be really useful for dev.

Jasper Kips <jasper@xxxxxxxxxxxxx> wrote:
>The problem lies in this statement: if(!$result1).
>Mysqli_query returns returns an object, except when the query fails.
>The query doesn't fail when the number of found rows is zero. So, if
>your query is syntactically correct, but there is no data found,
>$result1 is not false, but an object.
>Do a test for $result1->num_rows, like this: if ( 0 ===
>$result1->num_rows ) echo "No data found".
>
>Jasper
>
>Verstuurd vanaf mijn iPad
>
>> Op 22 jun. 2014 om 07:00 heeft "Ethan Rosenberg, PhD"
><erosenberg@xxxxxxxxxxxxxxxxxxxx> het volgende geschreven:
>> 
>> Dear List -
>> 
>> Here is a simple program.
>> 
>> It ran before, but not now...
>> 
>> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
>"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd";>
>> <html xmlns="http://www.w3.org/1999/xhtml";>
>> 
>> <html>
>>    <head>
>>    </head>
>>        <body>
>>            <div align="center">
>>            <form method="post">
>>            <input type='text' name=phone></input>
>>            <input type='submit'>
>>            <br /><br /><br />
>>            </form>
>>            </div>
>> <?php
>>            error_reporting(-1);
>>            require '/home/ethan/PHP/ethan.inc';
>>            $db = "Store";
>> $cxn = mysqli_connect($host,$user,$password,$db);            
>>            if (!$cxn)
>>            {
>>                die('Connect Error (' . mysqli_connect_errno() . ') '
>>                . mysqli_connect_error());
>>            }
>> 
>> //if no connection no error message
>>            
>>            $phn = $_POST[phone];
>> 
>> //Phone is a 10 digit numerical string, no spaces
>> 
>>            $phn = (string)$phn;
>>            
>>            $dsh = '-';
>>            $Phn =
>$phn[0].$phn[1].$phn[2].$dsh.$phn[3].$phn[4].$phn[5].$dsh.$phn[6].$phn[7].$phn[8].$phn[9];
>> 
>> //construct phone number 123-466-7890
>> 
>>            $sql1 ="select Lname, Fname from Customers where Phone =
>'$Phn' ";
>> 
>>            $result1 = mysqli_query($cxn, $sql1);
>>            if(!$result1)
>>            {
>> ?>                
>>                <div align="center">
>>                
>>                <strong>No Match Found</strong>
>>                <br /><br />
>>                </div>
>> <?php
>>            }
>> 
>> //if query fails, no error message.
>> 
>> 
>> //code to display query results, not listed.
>> 
>> 
>> 
>> TIA
>> 
>> Ethan
>> 
>> 
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>> 
>
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