You could either send information about which function you would like
to call on the url parameter ($_GET)
$.ajax('myserver.php?function=ajaxRetrieveData');
or adding into data object ($_GET or $_POST) :
$.ajax({
type: "POST",
url: "myserver.php",
data: { function: 'ajaxRetrieveData' }
});
and then using a router to find the function
myserver.php
$function = $_POST['function'];
$object->$function();
Please, do not use this code without properly validation.
2014-05-19 17:21 GMT-03:00 ICCSI <inungh@xxxxxxxxx>:
> I use following code for jQuery.ajax to call php.
>
> $.ajax('myserver.php")
>
> It seems that one php file only work for one jquery ajax code,
> Is it possible to have more than one function or one return different
> result in one php file?
>
> Your information and help is great appreciated,
>
> Regards,
>
>
> Iccsi,
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