Please familiarise yourself with the console in your browser. If you’re using Safari or Chrome there is a developer console built in, and if using Firefox I recommend installing Firebug. This error, and any others in your Javascript will be displayed in the console and this whole mailing list conversation could have been avoided. -Stuart -- Stuart Dallas 3ft9 Ltd http://3ft9.com/ On 30 Jan 2014, at 13:57, Adarsh Sharma <eddy.adarsh@xxxxxxxxx> wrote: > Thanks Stuart , issue is fixed. You got the root cause. > > Reports are coming now. > > Thanks > > > On Thu, Jan 30, 2014 at 7:19 PM, Adarsh Sharma <eddy.adarsh@xxxxxxxxx> wrote: > Hi Stuart, > > Please check below , ajaxDiv is at the end :- > > [root@]# cat index.html > <html> > <head> > <center><h1> OTRS Analysis </h1> > > > <script> > function week_report_fun(){ > var ajaxRequest; // The variable that makes Ajax possible! > > try{ > // Opera 8.0+, Firefox, Safari > ajaxRequest = new XMLHttpRequest(); > }catch (e){ > // Internet Explorer Browsers > try{ > ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP"); > }catch (e) { > try{ > ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP"); > }catch (e){ > // Something went wrong > alert("Your browser broke!"); > return false; > } > } > } > // Create a function that will receive data > // sent from the server and will update > // div section in the same page. > ajaxRequest.onreadystatechange = function(){ > if(ajaxRequest.readyState == 4 && ajaxRequest.status == 200){ > > var ajaxDisplay = document.getElementById('ajaxDiv'); > ajaxDisplay.innerHTML = ajaxRequest.responseText; > } > }i > var users = document.getElementById('users').value; > var queryString = "?users=" + users ; > > //document.write(users); > > ajaxRequest.open("GET","ajaxex.php?q="+users,true); > ajaxRequest.send(); > } > > </script> > </head> > <body> > > <form> > User : <select id="users"> > <option value="">Select a user</option> > <option value="133">an</option> > > <option value="168">ad</option> > <option value="78">sou</option> > > </select> > <input type='button' onclick="week_report_fun()" > value='Weekly Report'/> > </form> > <div id='ajaxDiv'>Your result will display here</div> > </body> > </html> > > > Please let me know if anything else is required > > Thanks > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
