> On Sun, 2013-08-04 at 14:56 +0430, Farzan Dalaee wrote:
>>
>> You mean when user logged in i add new record to table and when logged out i delete the row? So if user close the browser without logout how can i find user is online or not?
>>
>> Sent from my iPhone
>>
>> On Aug 4, 2013, at 14:44, Matijn Woudt <tijnema@xxxxxxxxx> wrote:
>>
>> >
>> >
>> >
>> > On Sun, Aug 4, 2013 at 11:02 AM, Farzan Dalaee <farzan.dalaee@xxxxxxxxx> wrote:
>> >> hi
>> >> i want to write online user module for my site and i want to check
>> >> $_SESSION['userID'] to find all users id who loged in
>> >> but when i echo this code its return only current user detail
>> >> how i can see all sessions?
>> >>
>> >> foreach($_SESSION as $k => $v)
>> >> {
>> >> echo $k."----------".$v;
>> >> }
>> >> or how i handle online users?
>> >
>> > You can only access sessions when you know the session id.
>> > Most sites handle online users in their database, store a timestamp each time a user loads a page. When you want to display the online users, check where the timestamp is between now and a few minutes ago. Note that without javascript (or flash/java/etc) there is no way to truly know if the user left or not. The session will stay active for a long time, depending on your php.ini settings.
>> >
>> > - Matijn
>> >
>
> Like Matijn said, unless you're using some kind of client-side method to continually poll the server, you can't know if they've just closed their browser. There are Javascript events for exiting a page, but they don't work correctly on Safari and iOS Safari.
>
> You don't have to actually save anything to the DB manually, just instruct PHP to use the DB for its own sessions, rather than files.
>
> Do you really need to inspect each visitors session in detail, or do you just need a way to determine how many unique visitors are on the site at any one time?
>
> Thanks,
> Ash
> http://www.ashleysheridan.co.uk
>
>
>
I need to inspect each visitor to show how online or who offline for chat
Like facebook chat
>
