On 1/3/2013 5:22 PM, Marc Fromm wrote:
Thanks Jonathan. I removed the date() syntax function and it works. From: Jonathan Sundquist [mailto:jsundquist@xxxxxxxxx] Sent: Thursday, January 03, 2013 2:16 PM To: Marc Fromm Cc: Serge Fonville; php-general@xxxxxxxxxxxxx Subject: Re: date problem Marc, When you take a date and do a strtotime you are converting it to an int which you can compare to each other much easier. So for your above example you would be best doing. define('WSOFFBEGIN','09/16/2012'); $jes = 01/03/2012; if ( strtotime($jes) < strtotime(WSOFFBEGIN) ) { $error = " MUST begin after " . WSOFFBEGIN . "\n"; } On Thu, Jan 3, 2013 at 4:12 PM, Marc Fromm <Marc.Fromm@xxxxxxx<mailto:Marc.Fromm@xxxxxxx>> wrote: Thanks for the reply. Every example on comparing dates in PHP that I found uses the "strtotime" function which I am using. What other type can I use? When is this example below supposed to work? // your first date coming from a mysql database (date fields) $dateA = '2008-03-01 13:34'; // your second date coming from a mysql database (date fields) $dateB = '2007-04-14 15:23'; if(strtotime<http://www.php.net/strtotime>($dateA) > strtotime<http://www.php.net/strtotime>($dateB)){ // bla bla } Thanks From: Serge Fonville [mailto:serge.fonville@xxxxxxxxx<mailto:serge.fonville@xxxxxxxxx>] Sent: Thursday, January 03, 2013 2:05 PM To: Marc Fromm Cc: php-general@xxxxxxxxxxxxx<mailto:php-general@xxxxxxxxxxxxx> Subject: Re: date problem Hi. date returns a string You should compare a different type for bigger/smaller than HTH Kind regards/met vriendelijke groet, Serge Fonville http://www.sergefonville.nl Convince Microsoft! They need to add TRUNCATE PARTITION in SQL Server https://connect.microsoft.com/SQLServer/feedback/details/417926/truncate-partition-of-partitioned-table 2013/1/3 Marc Fromm <Marc.Fromm@xxxxxxx<mailto:Marc.Fromm@xxxxxxx><mailto:Marc.Fromm@xxxxxxx<mailto:Marc.Fromm@xxxxxxx>>> I am comparing to dates. define('WSOFFBEGIN','09/16/2012'); $jes = 01/03/2012; if ( date("m/d/Y", strtotime($jes)) < date("m/d/Y", strtotime(WSOFFBEGIN)) ) { $error = " MUST begin after " . WSOFFBEGIN . "\n"; } I cannot figure out why the $error is being assigned inside the if statement, since the statement should be false. 01/03/2012 is not less than 09/16/2012. Marc
And hopefully put quotes around 01/03/2012. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
