All of the images are displaying because you're simply instructing the function to print out each file found with your call to glob(). The glob() function returns an indexed array containing files found in the path you specified, or an empty array if no files were found or false if glob() failed. When I say "print" I'm referring to you using the echo language construct, however, print is also another language construct.
Therefore using echo in your function allows the foreach loop to continue iterating through the array of files returned by glob(). Replacing that echo with the return, the function ones one iteration in the foreach loop and stops, returning that value. In your case, the function is returning index 0 of the array returned by glob().
Make more sense?
David McGlone <david@xxxxxxxxxxxxx> wrote:
>On Wednesday, October 03, 2012 08:55:29 PM admin wrote:
>> > Hi everyone, I have been playing around with some code the list
>helped me
>>
>> with a while back and I'm not grasping the concept between return and
>echo
>> and the PHP manual doesn't answer this, unless I'm missing something.
>There
>> is an > example at the very bottom of PHP's return manual, but it's
>> confusing.
>>
>> > So now I'm left wondering why return will only give me the first
>result in
>>
>> an array, but echo will give me all the results of the array. Using
>stuart's
>> example he had sent me a while back I've messed around with it and
>modified
>> it > to better understand it:
>> > function filename($prefix)
>> >
>> >{
>> >
>> > $matches = glob('images/property_pics/'.$prefix.'*');
>> > foreach($matches as $filename){
>> > return $filename;
>> >
>> > }
>> >
>> >}
>> >
>> >echo completeImageFilename($row['MLS_No']);
>> >
>> >With the above code I only get the first image of each picture name,
>but
>>
>> when I change return to echo, it groups and displays all the pics
>that have
>> the same picture name.
>>
>> >--
>> >David M.
>>
>> The first loop and return is all you will get.
>> Put the information into an array and return the array once the array
>is
>> built.
>
>I think I understand what your saying, but what I don't understand is
>that
>when I leave the current code intact and replace return $filename with
>echo
>$filename in the function, all the images display. Is this intended
>behavior
>between return and echo or is it just bad code on my part?
>
> --
>David M.
--
Sent from my Android phone with K-9 Mail. Please excuse my brevity.
