Re: Input variable from form help request

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On 29 Sep 2011 at 13:30, PHProg <phprog@xxxxxxxxxxxxxxxxxxx> wrote: 

> I'm trying to create a standard web form that will use a PHP script
> to copy a file from one server to another.

[snip]

> <?php
> if(!@copy('http://mydomain.com/files/".$_POST['trakname']."','/".$_POST['dirna
> me']."/".$_POST['trakname']."'))

This line:

  if(!@copy('http://mydomain.com/files/".$_POST['trakname']."','/".$_POST['dirname']."/".$_POST['trakname']."'))

looks like a big mess of single and double quotes to me. Why don't you go through it very carefully? I'd be inclined to make a small test program separate from the web page stuff and do things like:

<?php
$_POST['trakname'] = "abc";
// similar for the other two

$myvar = 'http://mydomain.com/files/".$_POST['trakname']."','/".$_POST['dirname']."/".$_POST['trakname']."';

echo $myvar;

?>

and fiddle until that works.

--
Cheers  --  Tim

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