On Monday, 18 April 2011 at 21:52, Ashley Sheridan wrote:
On Mon, 2011-04-18 at 21:41 +0100, Stuart Dallas wrote:
> > On Monday, 18 April 2011 at 21:27, Ashley Sheridan wrote:
> > I'm trying to get the usort function working inside of a class, but am
> > > having some issues. Basically, the compare function which is the second
> > > parameter isn't recognised, but I'm not really sure how to indicate
> > > exactly where it is.
> > >
> > > I've gone over the usort() docs and read the user comments, and the only
> > > thing I've found so far which looked like it was the same issue gave
> > > this example:
> > >
> > >
> > >
> > > bo at erichsen dot com 20-Mar-2001 01:16
> > > when using usort to refer to a function inside a class i have
> > > succesfully used:
> > >
> > > <?php usort($myarray,array($this,"cmp")); ?>
> > >
> > > Unfortunately, that doesn't work either. A basic example is as follows:
> > >
> > >
> > > class Search_model extends Model
> > > {
> > > function get_results($q)
> > > {
> > > if(strlen($q))
> > > {
> > > $results = array();
> > >
> > > $words = explode(' ', $q);
> > > sort($words);
> > >
> > > // build the basic match query parts to be used for the content and
> > > blog tables
> > > if(substr($words[0], 0, 1) == '+' || substr($words[0], 0, 1) == '-'
> > > || substr($words[0], 0, 1) == '"')
> > > {
> > > $queryP1 = "SELECT *, MATCH(`content`) AGAINST('$q' IN BOOLEAN MODE)
> > > AS `score` FROM";
> > > $queryP2 = "WHERE MATCH(`content`) AGAINST('$q' IN BOOLEAN MODE)";
> > > }
> > > else
> > > {
> > > $queryP1 = "SELECT *, MATCH(`content`) AGAINST('$q') AS `score`
> > > FROM";
> > > $queryP2 = "WHERE `display`='yes' AND MATCH(`content`)
> > > AGAINST('$q')";
> > > }
> > >
> > >
> > > $sql = "$queryP1 `content` $queryP2";
> > > $query = $this->db->query($sql);
> > > foreach($query->result() as $row)
> > > {
> > > $results[] = $row;
> > > $results[count($result)-1]->content_type = 'content';
> > > }
> > >
> > > usort($results, array($this, "content_score_sort"));
> > > }
> > > }
> > >
> > > function content_score_sort($a, $b)
> > > {
> > > // custom sort function to sort pages based on their score, which is
> > > an array value within each page
> > > if($a['score'] == $b['score'])
> > > return 0;
> > > else
> > > return ($a['score'] > $b['score']) ? -1 : 1;
> > > }
> > > }
> > >
> > > I know it's probably something very simple, but for the life of me I
> > > can't find what I'm missing.
> > >
> > > I think in part it's that the normal way I know of calling that sort
> > > function from within the class is $this->content_score_sort(), but that
> > > isn't recognised either.
> > >
> > > If anyone can shed any light on this it'd be very welcome!
> >
> > That is the correct way to specify it. Works fine for me: http://dev.stut.net/php/usort.php
> >
> > What makes you think it's not being recognised? I note that your get_results method doesn't actually return anything, so how do you know the sort isn't working?
> >
> > -Stuart
> Because I don't need it to return anything at that point, the usort call
> is within the get_results() method itself. Also, as I keep getting a
> variety of errors with the usort call I'm taking a wild guess that it
> doesn't work.
>
> With usort($results, array($this, "content_score_sort"));
> I get 'Fatal error: Cannot use object of type stdClass as array'
>
> usort($this->results, array($this, "content_score_sort")); gives
> 'Message: usort() expects parameter 1 to be array, null given'
>
> This is all built around a CodeIgniter class, but I figured this isn't
> really a CI question but a PHP one, however I'm still at a loss :-/
The usort call is at the end of the get_results method, and $results is local. If you want it to be a member of the class you need to set it as such.
I think you'll find your issue is that each element of $results will be an object, but in content_score_sort you're treating them as arrays. Change $a['score'] to $a->score and modify $b in the same way.
-Stuart
--
Stuart Dallas
3ft9 Ltd
http://3ft9.com/
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