Re: mysql_num_rows()

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"Pete Ford" <pete@xxxxxxxxxxxxx> wrote in message 
news:76.48.39221.054C36D4@xxxxxxxxxxxxxxx
> On 22/02/11 13:59, Gary wrote:
>> "Pete Ford"<pete@xxxxxxxxxxxxx>  wrote in message
>> news:A4.C0.39221.B3CA36D4@xxxxxxxxxxxxxxx
>>> On 22/02/11 05:40, Gary wrote:
>>>> Can someone tell me why this is not working?  I do not get an error
>>>> message,
>>>> the results are called and echo'd to screen, the count does not work, I
>>>> get
>>>> a 0 for a result...
>>>>
>>>>
>>>>
>>>> $result = mysql_query("SELECT * FROM `counties` WHERE name = 
>>>> 'checked'")
>>>> or
>>>> die(mysql_error());
>>>>
>>>> if ( isset($_POST['submit']) ) {
>>>> for($i=1; $i<=$_POST['counties']; $i++) {
>>>> if ( isset($_POST["county$i"] ) ) {
>>>> echo "You have chosen ". $_POST["county$i"]."<br/>";
>>>>           }
>>>>       }
>>>> }
>>>>
>>>> $county_total=mysql_num_rows($result);
>>>>
>>>> while($row = mysql_fetch_array($result))
>>>> {$i++;
>>>>       echo $row['name'];
>>>> }
>>>> $county_total=mysql_num_rows($result);
>>>> echo "$county_total";
>>>>
>>>> echo 'You Have '  .  "$county_total"  .  ' Counties ';
>>>>
>>>> ?>
>>>
>>> The first thing I see is that you do
>>>    $county_total=mysql_num_rows($result)
>>> twice. Now I'm not to sure, but it is possible that looping over
>>> mysql_fetch_array($result) moves an array pointer so the count is not
>>> valid after the operation... that's a long shot.
>>>
>>> But since you are looping over the database records anyway, why not just
>>> count them as you go? Isn't $i the number of counties after all the
>>> looping?
>>>
>>>
>>> --
>>> Peter Ford, Developer                 phone: 01580 893333 fax: 01580
>>> 893399
>>> Justcroft International Ltd.
>>> www.justcroft.com
>>> Justcroft House, High Street, Staplehurst, Kent   TN12 0AH   United
>>> Kingdom
>>> Registered in England and Wales: 2297906
>>> Registered office: Stag Gates House, 63/64 The Avenue, Southampton SO17
>>> 1XS
>>
>>
>> Peter
>>
>> Thank you for your reply.
>>
>> I did notice that I had the $county_total=mysql_num_rows($result) twice. 
>> I
>> had moved and removed it, always getting either a 0 or 1 result.
>>
>> I put up another test page with
>>
>> $result = mysql_query("SELECT * FROM `counties` ") or die(mysql_error());
>>
>> $tot=mysql_num_rows($result);
>> echo "$tot";
>>
>> ?>
>>
>> And it worked fine.
>>
>> I have tried count() as well as mysql_num_rows() but am getting the same
>> result.
>>
>> Could you explain what you mean by count them as I go?
>>
>> Again, Thank you for your reply.
>>
>> Gary
>>
>>
>>
>> __________ Information from ESET Smart Security, version of virus 
>> signature database 5895 (20110222) __________
>>
>> The message was checked by ESET Smart Security.
>>
>> http://www.eset.com
>>
>>
>>
>>
>
> Well,
>
> Lets go back to your original code and cut out the decoration:
>
> $result = mysql_query("SELECT * FROM `counties` WHERE name = 'checked'")
> $county_total=mysql_num_rows($result);
> while($row = mysql_fetch_array($result))
> {
>     echo $row['name'];
> }
> echo "$county_total";
>
> That code should do pretty much what you want...
>
> But, because you only show the number of records AFTER the loop, you could 
> do:
>
> $result = mysql_query("SELECT * FROM `counties` WHERE name = 'checked'")
> $county_total = 0;
> while($row = mysql_fetch_array($result))
> {
>     echo $row['name'];
>     $county_total++;
> }
> echo "$county_total";
>

Peter

Thank you for your suggestion...btw "cut out the decoration"  LOL

I'm sorry to report it did not work. I tried various configurations of it 
but to no avail.

Any other suggestions?

Again, thank you for your help.

Gary 



__________ Information from ESET Smart Security, version of virus signature database 5895 (20110222) __________

The message was checked by ESET Smart Security.

http://www.eset.com





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