Thanks for your reply "Deva" <devendra.in@xxxxxxxxx> wrote in message news:AANLkTimvyCQsi5nejD1LXxAqBQsB+q_oNhOC7OmGJ3Dz@xxxxxxxxxxxxxxxxx >I tried your script locally. Its working for me. > > On Tue, Feb 22, 2011 at 11:10 AM, Gary <gpaul@xxxxxxxxxxxxxxxx> wrote: > >> Can someone tell me why this is not working? I do not get an error >> message, >> the results are called and echo'd to screen, the count does not work, I >> get >> a 0 for a result... >> >> >> >> $result = mysql_query("SELECT * FROM `counties` WHERE name = 'checked'") >> or >> die(mysql_error()); >> >> if ( isset($_POST['submit']) ) { >> for($i=1; $i<=$_POST['counties']; $i++) { >> if ( isset($_POST["county$i"] ) ) { >> echo "You have chosen ". $_POST["county$i"]." <br/>"; >> } >> } >> } >> >> $county_total=mysql_num_rows($result); >> >> while($row = mysql_fetch_array($result)) >> {$i++; >> echo $row['name']; >> } >> $county_total=mysql_num_rows($result); >> echo "$county_total"; >> >> echo 'You Have ' . "$county_total" . ' Counties '; >> >> ?> >> -- >> Gary Thanks for your reply. I'm curious, how did you try it locally without a database? I am still getting either a 0 or a 1 for a result. Gary __________ Information from ESET Smart Security, version of virus signature database 5895 (20110222) __________ The message was checked by ESET Smart Security. http://www.eset.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
