Re: preg_replace question

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Am 24.01.2011 18:08, schrieb Alex Nikitin:
If you declare your arrays, and set k to 0 first, put quotes around array
values and use the correct limit (you can default to -1), you will get
results, here is code and example (hopefully this helps you)


<?php
        function internal_links($str, $links, $limit=-1) {
                $pattern=array();
                $replace=array();
                $k=0;
                foreach($links AS $link){
                        $pattern[$k] = "~\b({$link['phrase']})\b~i";
                        $replace[$k] = '<a href="'.$link['link'].'">\\1</a>';
                        $k++;
                }
                return preg_replace($pattern,$replace,$str, $limit);
        }

echo internal_links("süße knuffige Beagle Welpen ab sofort",
array(array('phrase'=>"beagle",
'link'=>"http://google.com";),array('phrase'=>"welpen",
'link'=>"http://wolframalpha.com";)), -1);

Output:
süße knuffige<a href="http://google.com";>Beagle</a>  <a href="
http://wolframalpha.com";>Welpen</a>  ab

~Alex


Hello,

thank you all for your help. It seems that I am building the array wrong. Your code works with that array:

$internal_links = array(array('phrase'=>"beagle", 'link'=>"http://google.com";),array('phrase'=>"welpen", 'link'=>"http://wolframalpha.com";));

I am pulling the data out of a DB and am using this code:
	while ($row = mysql_fetch_object($result)){		
		$internal_links[$row->ID]['phrase'] = $row->phrase;
		$internal_links[$row->ID]['link'] = $row->link;
	}	

You build the array different, could you help me to adapt this on my code? I tried $internal_links['phrase'][] as well, but that did not help either.

Thank you for any help,

Merlin

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