On 12/03/10 16:33, Tamara Temple wrote:
On Dec 2, 2010, at 11:33 PM, Da Rock wrote:
On 11/29/10 09:10, Richard Quadling wrote:
On 27 November 2010 04:45, Da
Rock<php-list@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote:
On 11/27/10 13:51, Tamara Temple wrote:
On Nov 26, 2010, at 7:28 PM, Da Rock wrote:
On 11/27/10 00:57, Richard Quadling wrote:
On 26 November 2010 00:07, Da
Rock<php-list@xxxxxxxxxxxxxxxxxxxxxxxxx>
wrote:
preg_match("/(\d{1,3})(\.)$/", exec($mixer . ' ' .
$command),&$matches)
Can you ...
var_dump(exec($mixer . ' ' . $command));
I wonder if the output includes a new line which you are not
accounting for in the regex.
Haven't tried yet, but isn't that what $ is for? End of line?
$ matches end of line, but since your last match expression is to
match
explicitly the character '.' before end of line, and there's a
newline, it
won't match. Again, use trim() to get rid of the newline character
at the
end of the string returned by exec(). Looking at the output or
And exec only gives one line- the last line of the output of the
command.
You have to provide a reference to an array for the entire output.
var_dump gives:
string(41) "Mixer vol is currently set to 75:75"
It also looks like \d{1,3}\. won't match anything in the output
string
given by the command.
Thank you for that- that did it. I removed the \.
I am a little confused though; that regex was tested on several
test sites
and was deemed accurate on them, and one of them actually supplied the
preg_match code. And if I run the command on a shell it actually
outputs
exactly the right subject for the regex- not to mention it got printed
inadvertently (using system() ) via the php exactly the same. So I
don't
think I missed it somehow.
What I have constantly seen come up (shell and php/html) is: Mixer
vol is
currently set to 75:75. (including the period)
Don't get me wrong- you guys make sense; my system doesn't. I need
to get to
the bottom of this so I can ensure my code will port well. I don't
want to
get it all working and find it breaks when I run it on another system,
albeit same OS (FreeBSD). Could be updates or variations of releases.
Just to check again, I ran the command on the shell again and sure
enough
the period is no longer there- but I can't for the life of me
figure out
when that changed as this code has never worked (and yes, I added
in the \.
to match the end of line because it originally wasn't working).
Another
great mystery? Weird... :)
Thanks again guys.
The regex is a valid regex. It's just useless for the data you are
providing it.
I'm wondering what is missing from your output? The var_dump says the
text is a 41 character string, but the data you provided only has 36
characters in it.
What elements of the string do you want to capture?
/:(\d++)/ would catch the number after the :
Apologies for the delay.
That works, except it will catch all instances. I need it to catch
the last number specifically and not the period. The output will also
output a previous and new reading- I need the new reading. And I also
need to allow for the possibility of a period. So.... here's what I
have:
/(\d++)[^.]?$
Which works as long as there is no period at the end. I just can't
seem to get my head around it. I need a guru... :)
Did you miss the ":" at the beginning of RIchard's suggested regex?
/:(\d++)/ would gather up all digits following a ":". If the output
from the mixer command is always something like dd:dd (irrespective of
trailing period), the regex above would always return the second set
of digits.
Sorry I probably didn't make it clear. The output can be the above or
"Setting the mixer vol from 70:70 to 75:75." Hence the $ for end of
line. So I obviously need the last number (75) and nothing else.
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