On 15 July 2010 16:51, Leonardo <leobasilio@xxxxxxxxx> wrote:
> Hi everybody. I need to use exec() to run a background php script, but it's
> not working properly. Take a look at this sample:
>
> a.php
> <?
>
> echo ' File A (1) ';
>
> exec('php b.php > output.txt &');
>
> echo ' File A (2) ';
>
> ?>
>
> b.php
> <?
>
> echo 'File B';
>
> ?>
>
> output.txt (begins with 64 null bytes before the following)
> File A (2)
>
> I would expect the output's content to be "File B", but it's not happening.
> I came across this problem because I have a mailing application which
> stopped working after being moved to a new host. The messages were sent by a
> background script launched on user's demand. Like this:
>
> SendMessages.php
> <?
> ...
> exec('php Daemon.php -x ' . $USERID . ' > /dev/null &');
> ...
> ?>
>
> Now it won't work, and I got no clue about what's going on. What now?
>
> Thank you.
>
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>
>
I'm on Windows XP SP3 and using
PHP 5.3.3RC3 (cli) (built: Jul 15 2010 02:00:11)
Copyright (c) 1997-2010 The PHP Group
All seems to work as expected.
<?php
// TestA.php
echo ' File A (1) ';
exec('C:\\php5\\php.exe -f Z:\\TestB.php > Z:\\output.txt');
echo ' File A (2) ';
?>
<?php
// TestB.php
echo 'File B';
?>
And because of my setup matching the docs at [1], I can actually use ...
<?php
echo ' File A (1) ';
exec('TestB > output.txt');
echo ' File A (2) ';
?>
as long as TestA.php and TestB.php are in the same directory.
So, initially, this looks like a non win32 issue (windows works - see !!!)
Regards,
Richard Quadling.
[1] http://docs.php.net/manual/en/install.windows.commandline.php
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