Re: String Parse Help for novice

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On Jun 13, 2010, at 5:35 PM, Rick Dwyer wrote:

OK, I get the following error:

Warning: basename() expects parameter 1 to be string, array given in....

When I use the following:

$thepath = parse_url($url);
$filename = basename($thepath);

Is my variable thepath not automatically string?

 --Rick

Oops I meant
echo($the_path);
or echo both and see.


Karl DeSaulniers
Design Drumm
http://designdrumm.com


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