Re: What's wrong with this code?

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Could the exit() be terminating it? Do you need this exit() as the else for that if statement? Try deleting just the else {}.

JAT

Karl

Sent from losPhone

On Jun 5, 2010, at 6:54 PM, David Mehler <dave.mehler@xxxxxxxxx> wrote:

Hello,
I've got a while loop outputting values from a database. Briefly it
looks like this:

while($row = mysql_fetch_array($result3))
{
echo "<tr>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['type'] . "</td>";
echo "<td>" . $row['startdate'] . "</td>";
if (!empty($row['EndDate'])) {
echo "<td>" . $row['enddate'] . "</td>";
} else {
exit();
}
echo "<td>" . $row['location'] . "</td>";
echo "<td>" . $row['summary'] . "</td>";
echo "<td>" . $row['description'] . "</td>";
echo "</tr>";
}

That's not the whole code, but it is the problem code. Some output has
the ending date set, one or two records i can't remember how many i
entered with one, most do not, i want the echo to be conditional. The
output stops right before the if statement, echoes startdate and
that's it, comment out the if block and it works fine.
Thanks.
Dave.

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