-----Original Message----- From: Ashley Sheridan [mailto:ash@xxxxxxxxxxxxxxxxxxxx] Sent: 22 April 2010 15:13 To: Dan Joseph Cc: PHP eMail List Subject: Re: Math Question.... On Thu, 2010-04-22 at 10:17 -0400, Dan Joseph wrote: > On Thu, Apr 22, 2010 at 10:12 AM, Stephen <stephen-d@xxxxxxxxxx> wrote: > > > 1,252,398 DIV 30 = 41,746 groups of 30. > > > > 1,252,398 MOD 30 = 18 items in last group > > > Well, the only problem with going that route, is the one group is not > equally sized to the others. 18 is ok for a group in this instance, but if > it was a remainder of only 1 or 2, there would be an issue. Which is where > I come to looking for a the right method to break it equally. > > > >How do you mean break it equally? If the number doesn't fit, then you've >got a remainder, and no math is going to change that. How do you want >that remainder distributed? > >Thanks, >Ash >http://www.ashleysheridan.co.uk > > > Perhaps a round-robin approach is called for? <? $items=1252398; $groupsize=30; for ($i=0;$i<$items;$i++) $grouparray[$i % $groupsize][]=$i; print_r($grouparray); ?> HTH J -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
