Hmm. OK with the help below, I am closer.
The other fields on the page are getting passed via form fields that
look like this:
input type="text" value="<?php echo check('element9'); ?>"
name="form[element9]" size="40" maxlength="255"
so I added:
input type="text" value="<?php echo check('my_id'); ?>"
name="form[my_id]" size="40" maxlength="255"
and formcheck.php has:
<?php
//start the session
session_start();
//array of fields in form. (In the format "field_name" => "field_label")
$form_fields = array(
"element0" => 'Your Name:',
"element1" => 'Your Email:',
"element4" => 'Item Number:',
.....
);
and I added:
"my_id" => 'My ID Is:',
And this works!
So when I am on mypage.php and I enter a value into the form field
"my_id" it carries over and repopulates should the form fail validation.
But upon initial load of the page from my link of mypage.php?my_id=5
(so I am not getting there via a form submit) how do I get the value
into the form field?
--Rick
On Feb 25, 2010, at 1:02 AM, viraj wrote:
if you do the redirection with header('Location: /mypage.php'),
setting a variable on formcheck.php is not enough.
if you modify the header('Location: /mypage.php') to..
header('Location: /mypage.php?my_id=5')
it will take the variable to mypage.php as $_GET['my_id]
you can not expect a variable value set in to $_POST array to reflect
on a totally different page without making it a form post (aka use of
proper headers).
i guess, it's time to you to read about session_start() method and the
array $_SESSION available in php :)
~viraj
On Thu, Feb 25, 2010 at 11:22 AM, Rick Dwyer <rpdwyer@xxxxxxxxxxxxx>
wrote:
OK... external function... that would explain why I could not
locate it.
Let me get right to the problem I am having with this code as
someone may be
able to help directly.
I have a link on a page that opens a contact form. The link is
mypage.php?my_id=5
So on mypage.php, I capture this value with:
$my_id=$_GET['my_id'];
I understand this much. But when the end user submits this contact
form
they do so to formcheck.php and if formcheck.php sees a required
field is
blank, it throws it back to mypage.php with an alert. BUT, I lose
the value
of the variable $my_id. SO, I created a hidden field on mypate.php
with
value="<?php echo $my_id; ?>" and on formcheck.php, I added $my_id =
$_Post['my_id'];
However, when formcheck.php returns me to mypage.php, $my_id is
still blank.
Very frustrating.
Any help determining what I am doing wrong is greatly appreciated.
Thanks.
--Rick
On Feb 25, 2010, at 12:31 AM, Paul M Foster wrote:
On Thu, Feb 25, 2010 at 12:16:08AM -0500, Robert Cummings wrote:
Rick Dwyer wrote:
Hello all.
I'm trying to learn PHP on the fly and I have a line of code that
contains syntax I can't find documented anywhere:
php echo check('element8');
In the above line, can someone tell me what "check" means?
In the above, check is a function. It is being called with
parameter
'element8'.
This is true. But perhaps more importantly, check() is not a
native PHP
function. Thus it comes from some other library or group of external
functions.
Paul
--
Paul M. Foster
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~viraj
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