Re: please help with regular expression in preg_replace

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Red wrote:
> hello, im not a php developer, i just need to rewrite one php file but having problem with understanding syntax of regexp in php.
> 
> i need to get domain name from fqdn (for example from $_SERVER['HTTP_HOST'] )
> 
> in sed its working well with "s/[^.]*\.//" , but preg_replace behaves weird.
> 
> 
> http_host is for example hostname.domain.com
> 
> <?php
> $host = $_SERVER['HTTP_HOST'];
> exec( "echo $host | sed s/[^.]*\.//", $domain ) ;
> echo "$domain[0]"
> ?>
> 
> return "domain.com", but
> 
> <?php
> $host = $_SERVER['HTTP_HOST'];
> $domain = preg_replace( '/[^.]*\./' , '', $host) ;
> echo "$domain";
> ?>
> 
> return only "com"
> 
> i think when this php page get many hits, its not so wise to call sed everytime, i would like to ask someone for help how to write preg_replace pattern.
> 
> thanx 
> 
> Rene
> 

I would add one thing and change another.

<?php
$host = $_SERVER['HTTP_HOST'];
$domain = preg_replace( '/^[^.]+\./' , '', $host) ;
echo $domain;
?>

Adding an additional '^' to the start tells it to start at the beginning.
And changing '*' to a '+'

Jim

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