There is no best function as such. Everything depends upon your requirement. You can also use fopen() to get the contents of the remote file and do some error handling that if you get any content then display image else a message etc.. Gaurav Kumar (Team Lead- open source) oswebstudio.com On Wed, Sep 16, 2009 at 4:06 AM, CRM <crm@xxxxxxxxxxxxxx> wrote: > Hi All, > Not sure of the best approach, need your feedback. I have 4 images on a > website. These are used in navigation. When I load a reference webpage on > my > local machine the local page calls 4 images from an external website, each > image will be on a different domain. > > What I want to see is if the navigation images/buttons can be > loaded/displayed > in my browser. If they can, then I will display the images on my local > page. > If the images cannot be loaded, then this indicates some connection issue > and > the result will be some text like 'Site Offline'. So just by glancing at my > local machine reference page I can tell if one or more of the different > sites > is or is not available. > > So what is the best function to use? > > if ( @file_get_contents( DOMAIN_PATH . > "images/navigation/nav_globalissa.png" )): > > or ??? > > Please also cc info@xxxxxxxxxxxxxx > > Thanks for any helpful suggestions. > > Sincerely, > > Rob > Global I.S. S.A. > Software Powers the Net > Email: crm at globalissa dot com > > * * * The Forge of Globalissa ~ PHP Foobar Machine * * * > http://globalissa.com/forge/ > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >
