__destruct is called only when the object is detroyed.
The object is destroyed only when there is no references to it.
<?php
error_reporting( E_ALL | E_STRICT );
header( 'Content-Type: text/plain' );
class Foo
{
function __destruct()
{
echo __METHOD__, PHP_EOL;
}
}
$a = new Foo;
$b = $a; # <<<< try the script without this line or commented
unset( $a ); # no destructor called
echo '--', PHP_EOL;
unset( $b ); # destructor called!
On Mon, Aug 24, 2009 at 8:40 PM, Ralph Deffke <ralph_deffke@xxxxxxxx> wrote:
>
> well I would call this an error in the first view , and some of u where
> right! and the stuff with the refernce counter seems to be right as well.
>
> however I can't see a reason for it as 5.x works through refernces. so
> unsetting a REFERENCE to the object does not destroy it.
>
> How to destroy the object then?
>
> <?php
>
>
> abstract class a {
> public function __construct(){
> echo "constructing....<br>";
> }
> public function __destruct(){
> echo "destructing....<br>";
> }
> }
>
> class b extends a{
>
> public function doSomething(){
> echo "I'm doing ...but the reference c to the object is unset()<br>";
> }
>
> }
>
> $c = new b();
>
> $d = $c ; // works
> $f[] = $c ; // works
>
> class e {
> public static $m;
>
> public static function setM( $m ){
> self::$m = $m;
> }
> }
>
> $o = new e();
> e::setM( $c ); // works
>
> echo "unsetting ...<br>";
> unset( $c );
>
> $d->doSomething();
>
> echo "script ending now ...<br>";
>
> ?>
>
>
>
>
> --
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>
>
--
Martin Scotta
