$rs->Fields(22) equals a NULL in the database My Code: if(empty($rs->Fields(22))){ $q4 = ""; }else{ $q4 = $rs->Fields(22); } Produces this error: Fatal error: Can't use method return value in write context in D:\Inetpub\wwwroot\evaluations\lookup2.php on line 32 Line 32 is the "if" line... If I switch the code to (using is_null): if(is_null($rs->Fields(22))){ $q4 = ""; }else{ $q4 = $rs->Fields(22); } It produces this error: Catchable fatal error: Object of class variant could not be converted to string in D:\Inetpub\wwwroot\evaluations\lookup2.php on line 196 Line 196 is: <?php echo $q4;?> What am I doing wrong? Thanks! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php