Re: Another date exercise

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2009/8/19 Shawn McKenzie <shawn@xxxxxxxxxxxxx>

> Shawn McKenzie wrote:
> > tedd wrote:
> >> At 3:40 PM +0530 8/17/09, kranthi wrote:
> >>> dont you think http://in3.php.net/strtotime is a solution to your
> >>> problem ?
> >> No, it's not a solution to my problem -- I have he problem solved.
> >>
> >> I was just asking if anyone wanted to submit their php solution. It was
> >> only an exercise.
> >>
> >> I know there are numerous javascript solutions (some good, some bad),
> >> but ALL of their data has to be accepted and scrubbed by a php script
> >> anyway, so I was suggesting creating a php script to do it.
> >>
> >> If it's not a good exercise, then don't do it.
> >
> > First stab at it.  Of course it needs US date ordering (month day year).
> >  You can't do euro type dates or any other format because there is no
> > way to tell the difference between 1/2/2009 (January) and 1/2/2009
> > (February):
> >
> > <?php
> >
> > $dates = array(
> > 'August 5, 2009',
> > 'Aug 05 2009',
> > 'Aug 5, 9',
> > '08/05/09',
> > '8-5-9',
> > '8 05 2009',
> > '8,5,9',);
> >
> > foreach($dates as $date) {
> >     $date = preg_replace("#([\d])+[^/\d]+([\d]+)[^/\d]+([\d]+)#",
> > "$1/$2/$3", $date);
> >     echo date("M j, Y", strtotime($date)) ."\n";
> > }
> >
> > ?>
> >
>
> Guess you didn't like this one?  Also, if you change the / to - in the
> preg_replace() it should work on Euro style dates.
>
> $date = preg_replace("#([\d])+[^-\d]+([\d]+)[^-\d]+([\d]+)#",
> "$1-$2-$3", $date);
>
> -Shawn
>
> --
> PHP General Mailing List (http://www.php.net/)
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>
>
Perhaps you could detect the region of the user to pick which kind of date
to use

-- 
Luke Slater
:O)

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