Re: use preg_replace to nix and line with "display: none"

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Yay!  That worked.  Thanks!


On Aug 9, 2009, at 1:53 AM, Michael A. Peters wrote:

Rob Gould wrote:
I have a bunch of bullets in a list coming from a previous post, and I need to eliminate any line from this string that contains "display: none" <li id="bullet_ug1_col2_9" style="display: list-item;">Reserved Frontstretch Tower Ticket to the Camping World 300 on Saturday </li> <li id="bullet_2_9" style="display: list-item;">Reserved Frontstretch Tower Ticket to the Daytona 500 on Sunday </li>
<li id="bullet_addon_col2_9" style="display: none;"/>
<li id="bullet_addon3_9" style="display: none;"/>
<li id="bullet_option2_col4_9" style="display: none;"/>
<li id="bullet_option2_col3_9" style="display: none;"/>
<li id="bullet_option2_col2_9" style="display: none;"/>
<li id="bullet_option2_col1_9" style="display: none;"/>
<li id="bullet_option3_col4_9" style="display: none;"/>
<li id="bullet_option3_col3_9" style="display: none;"/>
<li id="bullet_option3_col2_9" style="display: none;"/>
<li id="bullet_option3_col1_9" style="display: none;"/>
<li id="bullet_option4_col4_9" style="display: none;"/>
<li id="bullet_option4_col3_9" style="display: none;"/>
<li id="bullet_option4_col2_9" style="display: none;"/>
<li id="bullet_option4_col1_9" style="display: none;"/>
<li id="bullet_option5_col4_9" style="display: none;"/>
<li id="bullet_option5_col3_9" style="display: none;"/>
<li id="bullet_option5_col2_9" style="display: none;"/>
<li id="bullet_option5_col1_9" style="display: none;"/>
<li id="bullet_5_9">Official Daytona 500 Race Week Program </li>
<li id="bullet_6_9">Benchwarmer Sports Souvenir Ticket Protector and Lanyard </li>
<li id="bullet_7_9">On Site Benchwarmer Tour Staff </li>
<li id="bullet_8_9">All Taxes and Service Charges</li>
I'm CLOSE, but since the style = "display:[space]none" my preg_replace doesn't catch it. Can anyone help me determine the correct preg_replace pattern to do this?
$bl = $_POST['bulletlist'];
$pattern = '|^.+?display:none.+?$|mi';
$bl = preg_replace($pattern,'',$bl);

Easy to do with xml tools if your input is easily manipulated by xml tools, but try this:

$pattern = '/<li[^>]*style="display: none[^>]*>/';

not tried myself.


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