Am I missing something? Can't this be done quickly/easily with preg_match()?
if (preg_match('/\[(.*):(.*)\s/U', '[21/Jul/2009:00:00:47 -0300]',
$matches)) {
print "date: {$matches[1]}, time: {$matches[2]}";
}
Jerry Wilborn
jerrywilborn@xxxxxxxxx
On Tue, Aug 4, 2009 at 5:36 AM, Wolf <LoneWolf@xxxxxxxxx> wrote:
> Paul Halliday wrote:
> > Whats the cleanest (I have a really ugly) way to break this:
> >
> > [21/Jul/2009:00:00:47 -0300]
> >
> > into:
> >
> > date=21/jul/2009
> > time=00:00:47
> >
> > Caveats:
> >
> > 1) if the day is < 10 the beginning of the string will look like
> "[<space>1/...
> > 2) the "-0300" will differ depending on DST or TZ. I don't need it
> > though, it just happens to be there.
> >
> > This is what I have (it works unless day < 10):
> >
> > $theParts = split("[\"]", $theCLF);
> >
> > // IP and date/time
> > $tmpParts = explode(" ", $theParts[0]);
> > $theIP = $tmpParts[0];
> > $x = explode(":", $tmpParts[3]);
> > $theDate = str_replace("[","", $x[0]);
> > $theTime = "$x[1]:$x[2]:$x[3]";
> >
> > the full text for this part looks like:
> >
> > 10.0.0.1 - - [21/Jul/2009:00:00:47 -0300] ... more stuff here
> >
> > Anyway, any help would be appreciated.
> >
> > thanks.
> >
>
> unset ($STRING,$pos,$pos2,$pos3,$L,$D,$T,$pos4,$NString);
> $STRING="10.0.0.1 - - [21/Jul/2009:00:00:47 -0300] ... more stuff here"
> $pos=strpos($STRING,"[");
> $pos2=strpos($STRING,"]");
> $L=$pos2-$pos;
> $NString=substr($STRING,$pos,$L);
> $pos3=strpos($NString,":");
> $D=substr($NString,0,$pos3);
> $pos4=$pos3++;
> $T=substr($NString,$pos4,8);
> echo "date=$D";
> echo "time=$T";
>
> untested, but that should be pretty much all you need.
>
> HTH,
> Wolf
>
>
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