Re: isset not functioning -RESOLVED

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

 



Thanks!

On Mon, Aug 3, 2009 at 10:13 AM, Andrew Ballard <aballard@xxxxxxxxx> wrote:

>  On Mon, Aug 3, 2009 at 1:08 PM, Allen McCabe<allenmccabe@xxxxxxxxx>
> wrote:
> > I created a simple survey for my work website, most of the PHP is on my
> > process.php document, which is referenced by a form on a seperate page
> > containing the form with the method of "post".
> >
> > On my process.php page, the script obtains the field data using the
> > $_REQUEST[] function.
> >
> > I have a small if statement to check to see if they filled out the
> > 'firstname' field, and if they did not, to replace $name with "Sir or
> > Madam". Unfortunately, $name always equals "Sir or Madam", wether a value
> > for "firstname" was entered or not.
> >
> > All the of the other instances of using $_REQUEST[] functions just fine,
> but
> > don't make use of if or isset. Here is the code snippet:
> >
> > if(isset($_REQUEST['firstname']) && !empty($RESULT['firstname'])) {
> >  $name = $_REQUEST['firstname'];
> >  } else {
> >  $name = 'Sir or Madam';
> > }
> >
> > I also tried adding an underscore to $RESULT (I got the code for this
> from a
> > php.net comment on the manual), to make it $_RESULT, but this doesn't
> seem
> > to be a pre-set function, and it still does not make it work. I am
> guessing
> > the user neglected to define $RESULT in his snippet, or I overlooked it.
> >
> > Can anyone see any problems with the code?
> >
>
> You are switching from $_REQUEST to $RESULT. Trying to use $_RESULT
> won't make it any better.
>
> Andrew
>

[Index of Archives]     [PHP Home]     [Apache Users]     [PHP on Windows]     [Kernel Newbies]     [PHP Install]     [PHP Classes]     [Pear]     [Postgresql]     [Postgresql PHP]     [PHP on Windows]     [PHP Database Programming]     [PHP SOAP]

  Powered by Linux