It's exactly what I would expect... The content of the row... But in
any case, what does changing the content of the { } branch have to do
with how the IF() itself is evaluated?
array(4) {
[0]=>
string(8) "CustName"
["config"]=>
string(8) "CustName"
[1]=>
string(11) "Sample Cust"
["value"]=>
string(11) "Sample Cust"
}
On Tue, Jul 28, 2009 at 2:56 PM, Eddie Drapkin<oorza2k5@xxxxxxxxx> wrote:
> On Tue, Jul 28, 2009 at 2:48 PM, Matt Neimeyer<matt@xxxxxxxxxxxx> wrote:
>> Background: I'm converting a webapp from Visual FoxPro as a backend to
>> MySQL... However one part of our app (a system status checker) is
>> common code between the versions.
>>
>> I've got the following function... In English (in case it's not
>> apparent), if the version of the app is 2.0 or higher, then use MySQL
>> functions, otherwise use the ODBTP function to connect to VFP.
>>
>> function my_fetch_array($result)
>> {
>> global $Version;
>> if(version_compare($Version,"2.0",">="))
>> { $Ret = mysql_fetch_array($result); if(!$Ret) { } else { return $Ret; } }
>> else { $Ret = odbtp_fetch_array($result); if(!$Ret) { } else { return $Ret; } }
>> }
>>
>> This feels like a hack but works perfectly. Data is returned and all
>> is right with the world. Until I added in extra "error reporting".
>> When I change the if(!$Ret) portion as such...
>>
>> if(!$Ret) { die("myError".mysql_error()); } else { return $Ret; }
>>
>> It ALWAYS dies... and I see "myError" on the screen... If I change it
>> like such...
>>
>> if(!$Ret) { } else { echo "notError"; return $Ret; }
>>
>> I always see the "notError" on the screen and $Ret gets returned.
>>
>> WHY does adding the die() inside the { } change the way the if is evaluated?
>>
>> By the way I've tested this on 4.4.x on OSX and Windows, and on 5.2.5
>> on Windows...
>>
>> Thanks
>>
>> Matt
>>
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>>
>>
>
> What's the output of var_dump($Ret) right before that if statement?
>
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