Re: Re: Displaying images

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On Thu, May 28, 2009 at 3:06 PM, Miller, Terion <
tmiller@xxxxxxxxxxxxxxxxxxxx> wrote:

>
>
>
> Well I have tried Numerous scripts and ways and still can't get the image
> to display.
>
> I have echoed the file and have been able to get the gibberish image code
> to display but not a real image, here is my full code if anyone wants to
> have a look, I am going crossed eyed here.
>
>
>
>
>
> These are just a few of the ways I have been trying to get the img tag to
> work on my output.php page:
>
>       <tr>            <td>Scout Photo:</td>              <td>
>  <a href="image.php?filename=<?php echo$row['photoName']; ?>"><?php
> echo$row['photoName']; ?></A><br>                            <?php echo
> "\n<br>Scout Photo : "."<img src=\image.php?filename=" .$row['photoName'].
> "\">"; ?>                                          <?php echo "<img
> src=\"image.php?filename=".$row['photoName']."\">\n"; ?>
>        <?php echo "<img src=\"image.php?id=".$row['ePID']."\">\n"; ?>
>                      <img src="image2.php?filename=<?php echo
> $row['photoName']; ?>">
>
>
> Here is one way I was trying to get to work for the image.php page where
> the headers are supposed to work and don't
>
> include("inc/dbconn_open.php");
> error_reporting(E_ALL);
>
>
> //if (isset($_FILES['ePhoto'])){$ePhoto = $_FILES['ePhoto'];} else {$ePhoto
> ="";}
>
> $filename = $_GET['$filename'];
>
> $image = stripslashes($_REQUEST[photoName]);
>
> $sql = "SELECT ePhoto, photoName, photoType from eagleProjects WHERE
> photoName = $filename";
> $result=mysql_query($sql);
> $data = mysql_fetch_array ($result);
>
>
>
> $type = $data['photoType'];
> $name = $data['photoName'];
>
>  header("Content-type: $type");
>  header("Content-Disposition: attachment; filename=$name");
>
>
> echo $data["photoName"];
> echo $data["ePhoto"];
>
> exit;
>

Terin,

I just gave the same code to another person on another forum and he had no
issues getting that to work. If it does not work, you will need to ensure
that the value you pass to the show_image file is the same value that you
are using to look up the image. So if its an id number make sure you are
using the same id field to look up the image.

-- 

Bastien

Cat, the other other white meat

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