Thanks, but I solved the problem another way. http://codepad.org/6juIkECZ. On Sun, May 3, 2009 at 3:02 PM, Michael A. Peters <mpeters@xxxxxxx> wrote: > Andrew Hucks wrote: >> >> Got this error: >> >> Fatal error: Cannot instantiate non-existent class: finfo in <place> on >> line 6 > > You need the pecl-FileInfo module. > You can just comment that out that line and the line after it and (assuming > all your images are png) change > > $mime_type = $fi->buffer(file_get_contents($impath)); > > to > > $mime_type = 'image/png'; > >> >> On Sun, May 3, 2009 at 12:58 AM, Michael A. Peters <mpeters@xxxxxxx> >> wrote: >>> >>> Andrew Hucks wrote: >>>> >>>> Is it possible to rename images dynamically? >>>> >>>> Say that I had something like image1.png, and I don't want to rename >>>> it on the server. I'm working on an image rotater for a forum that >>>> doesn't allow anything but image files as signatures. >>>> >>>> Here's my code so far: >>>> >>>> <?php >>>> >>>> //LolRotator >>>> >>>> //add images. not too hard. >>>> $images = array("image1.png", "image2.png", "image3.png"); >>>> //which one do we gets? >>>> $show = rand(0, (count($images)-1)); >>>> //i r got u picture. >>>> echo '<img src="'.$images[$show].'"/>'; >>>> >>>> ?> >>>> >>>> I used mod_rewrite, which makes it from image.php to image.png. But, >>>> because the files aren't named image.png, it doesn't work. I need to >>>> figure out somethign between lines 8 and 10 to change the file name to >>>> image.png. >>> >>> Use mod_rewrite so that request for image.png is handled by a script, >>> image.php >>> >>> image.php then randomly picks a image file from list, sends the >>> appropriate >>> image header, and reads the file sending the content to the browser. IE - >>> >>> function sendimage($impath) { >>> // requires fedora rpm : php-pecl-Fileinfo >>> $fi = new finfo(FILEINFO_MIME); >>> $mime_type = $fi->buffer(file_get_contents($impath)); >>> $imageOutput = ""; >>> if ($fp = fopen( $impath , 'rb' )) { >>> while ($l = fgets($fp)) { >>> $imageOutput .= $l; >>> } >>> $outputLen = strlen($imageOutput); >>> header("Content-Length: $outputLen"); >>> header("Content-type: $mime_type"); >>> print $imageOutput; >>> } else { >>> // for whatever reason we failed >>> die(); >>> } >>> } >>> >>> >>> >>>> Is there a way to do this? >>>> >>> >> > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
