On 26 April 2009 22:59, PJ advised: > kranthi wrote: >> if $Count1 is never referenced after this, then certainly this >> assignment operation is redundent. but assignment is not the ONLY >> operation of this statement. if u hav not noticed a post increment >> operator has been used which will affect the value of $Count as well, >> and this operation is required for the script to work. >> >> the script should work even if u replace >> $Count1 = $Count++; >> with >> $Count++; >> >> Kranthi. >> >> > Not quite, since that would change the $Count variable and > that is used > leater in the code. Um -- I must be missing something here, because those two statements have exactly the same effect on $Count, incrementing it by one (and you said the first statement fixed your problem, so logically the second one must too). In fact, because you've used a post-increment, the statement $Count1 = $Count++; ends up with $Count == $Count1+1, and $Count1 being the original value of $Count!! This whole scenario smacks to me of a classic "off-by-one" error -- either $Count actually *needs* to be one greater than the value you first thought of, or some other value you are comparing it to should be one smaller than it actually is. Cheers! Mike -- Mike Ford, Electronic Information Developer, C507, Leeds Metropolitan University, Civic Quarter Campus, Woodhouse Lane, LEEDS, LS1 3HE, United Kingdom Email: m.ford@xxxxxxxxxxxxxx Tel: +44 113 812 4730 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
