On 3/12/2009 9:39 AM, "TG" <tg-php@xxxxxxxxxxxxxxxxxxxxxx> wrote: > $currmonth = date("m"); > > for ($i = 1; $i <= 11; $i++) { > $m[$i] = date("m/d/y"), mktime(0,0,0,$currmonth-$i, 1, 2009)); > } > > Something like that. mktime() is remarkably flexible. If you start on > month 3 and you subtract 5, you get month = -2. So that would be > -2/1/2009, which mktime will translate to 11/1/2008. > > This is totally off the top of my head, but you get the idea. Works with > days and years too. Sometimes it's useful when going backwards and not > sure how many days the previous month had (without doing another call to > find out). > > -TG SOLVED - Thanks so much Andrew & TG >From your examples - I was able to create this working table going back 2 years - thanks again! ============ <table border="1" cellspacing="2" cellpadding="2"> <tr> <td>Dates</td> </tr> <?php $currmonth = date("m"); $curryear = date("y"); $i = 0; do { ?> <tr> <td><?php $m[$i] = date("m/d/y", mktime(0,0,0,$currmonth-$i, 1, $curryear)); echo $m[$i].'<br />'; $i++ ?> </td> </tr> <?php } while ($i < 25); ?> </table> -- Thanks - RevDave Cool @ hosting4days . com [db-lists 09] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php