On Thu, Feb 26, 2009 at 06:07:02PM -0500, PJ wrote:
> Is there a shorter way of determining if a field contains text?
> This works but I wonder if I can K.I.S.S. it? I really only need to know
> if there is or is not a field containing the text specified. I don't
> need to see it.
> <?php
>
> // Request the text
> $text = "Joe of Egypt";
> $sql = "SELECT title FROM book WHERE title LIKE '$text'";
> $result = mysql_query($sql);
> if (!$result) {
> echo("<P>Error performing query: " .
> mysql_error() . "</P>");
> exit();
> }
>
> // Display the text
> while ( $row = mysql_fetch_array($result) ) {
> echo("<P>" . $row["title"] . "</P>");
> }
> if ($row["title"] == "")
> echo ("Empty!")
>
> ?>
If you just want to see whether the passed text is in the title field,
and not display it, then no, there's no simpler way. However, I would
suggest you surround the $text with percent signs (%) to allow mysql to
check if this text is embedded within any of the titles. (Er, that's the
way you do it in PostgreSQL; I assume MySQL uses the same mechanism.)
Also, I don't know that mysql_query() returns *false* on no rows. I
generally check that with mysql_num_rows(). Again, I don't know MySQL
that well. PostgreSQL only returns *false* if there's a problem with the
query. If the query yields nothing, then you have to check with
pg_num_rows().
Paul
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Paul M. Foster
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