On Wed, Jan 28, 2009 at 4:31 PM, Terion Miller <webdev.terion@xxxxxxxxx> wrote: > On Wed, Jan 28, 2009 at 3:22 PM, Christoph Boget <christoph.boget@xxxxxxxxx> > wrote: >> >> > Well I'm stuck I have the AdminID but now I can't seem to use it to pull >> > workorders with that AdminID . I couldn't get your block to work Andrew >> > :( >> > I think I'm just not using it right now that I have it...lol >> >> Because there is ambiguity w/r/t the columns you are selecting, you'll >> need to use aliases. >> >> http://dev.mysql.com/doc/refman/5.1/en/identifiers.html >> >> In your code, when you are referencing the column, do so using the >> alias. That should solve your problem. >> >> thnx, >> Christoph >> > I just read it 3 times and I don't understand it. > Try this... (just make sure to assign a valid $username value.) $sql = "SELECT workorders.WorkOrderID , workorders.AdminID FROM workorders INNER JOIN admin ON workorders.AdminID = admin.AdminID WHERE admin.UserName = '" . mysql_real_escape_string($username) . "'"; Andrew -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
