SELECT into array of arrays

[Andrej Kastrin <andrej.kastrin@xxxxxxxxx>]

Dear all,

I have a MySQL table 'test' which includes two columns: 'study' and 
'symbol':

study symbol
a2008 A
a2008 B
a2008 C
a2008 D
b2005 A
b2005 B
b2005 E


Using POST variable I passed 'study' values into $myArray:

// $myArray is variable length; used only two values in example
$myArray = array("a2008","b2005");


Then I try to produce the following structure (array of arrays):

$combinedArray = array(array('A','B','C','D'),array('A','B','E'));


Below is my php script. In the present solution the $combinedArray 
includes only 'symbol' values for last iteration (where $myArray = "b2005").

How should I proceed? Thanks in advance for any suggestions.

Best, Andrej



$combinedArray = array();
for ($i=0;$i<count($myArray);$i++) {

$sql = "SELECT study,symbol FROM test WHERE study IN ('$myArray[$i]')";
$result = mysql_query($sql);

if(mysql_num_rows($result) > 0) {
    while ($myrow = mysql_fetch_array($result)) {
        $combinedArray[] = $myrow['symbol'];
    }
}
}

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