Re: Help with understanding an error

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this was the code I posted that accidentally only went to Wolf:

what does  STFW mean?

<?php
include("inc/dbconn_open.php");

if (empty($_SESSION['AdminLogin']) OR $_SESSION['AdminLogin'] <> 'OK' ){
?>
    <script language="javascript">
        window.close();
    </script>
<?php
    exit();
}

if (isset($_POST['AdminID'])){
    $AdminID = $_POST['AdminID'];
} elseif (isset($_GET['AdminID'])){
    $AdminID = $_GET['AdminID'];
} else {
?>
    <script language="javascript">
        window.close();
    </script>
<?php
    exit();
}

if (isset($_POST['WorkOrderID'])){
    $WorkOrderID = $_POST['WorkOrderID'];
} elseif (isset($_GET['WorkOrderID'])){
    $WorkOrderID = $_GET['WorkOrderID'];
} else {
?>
    <script language="javascript">
        window.close();
    </script>
<?php
    exit();
}

if (isset($_POST['ReturnPage'])){
    $ReturnPage = $_POST['ReturnPage'];
} elseif (isset($_GET['ReturnPage'])){
    $ReturnPage = $_GET['ReturnPage'];
} else {
    $ReturnPage = "Welcome.php";
}

$sql = "SELECT WorkOrderID, CreatedDate, IONumber, OrderType,
WorkOrderNumber, Advertiser, AccountNum, Address, City, ";
$sql .= "State, Zip, Phone, Fax, ContactName, URL, AdvertisingAgency,
ClickThru, Impressions, AdSize, ";
$sql .= "DATE_FORMAT(StartDate, '%m/%e/%Y') AS StartDates,
DATE_FORMAT(EndDate, '%m/%e/%Y') AS EndDates, CPM, FlatRate, ";
$sql .= "IncludeSites, Package, Matrix, DATE_FORMAT(MatrixDate, '%m/%e/%Y')
AS MatrixDates, Salesperson, SalespersonID, ";
$sql .= "SalespersonEmail, SalespersonExt, NameCampaign,
SpecialInstructions, AdContactName, AdContactPhone, AdContactEmail, ";
$sql .= "Artwork, DATE_FORMAT(PrintDate, '%m/%e/%Y') AS PrintDates,
ElectronicAd, EmailProof, ";
$sql .= "DATE_FORMAT(ProofDate, '%m/%e/%Y') AS ProofDates, ArtInstructions,
Focus, BannerSize, BannerSizeOther, BannerType, ";
$sql .= "BannerTypeOther, ExtraImage1, ExtraImage1Desc, ExtraImage2,
ExtraImage2Desc, ExtraImage3, ExtraImage3Desc, ";
$sql .= "ExtraImage4, ExtraImage4Desc, ExtraImage5, ExtraImage5Desc FROM
workorderform WHERE WorkOrderID='$WorkOrderID'";
$result = mysql_query ($sql);
$row = mysql_fetch_object ($result);

$sql2 = "SELECT Date_FORMAT(CreatedDate,'%m/%e/%Y %h:%i %p') AS OrderDate,
Location, WorkOrderName, Status FROM workorders ";
$sql2 .= "WHERE WorkOrderID='$WorkOrderID'";
$result2 = mysql_query ($sql2);
$row2 = mysql_fetch_object ($result2);


if (mysql_num_rows($result) == 0) {
?>
    <script language="javascript">
        window.close();
    </script>
<?php
    exit();
}
?>


On Mon, Nov 24, 2008 at 11:32 AM, Wolf <lonewolf@xxxxxxxxx> wrote:

>
> ---- Terion Miller <webdev.terion@xxxxxxxxx> wrote:
> > Can anyone help explain what I need to do to fix this:
> >
> > Error: *Warning*: mysql_fetch_object(): supplied argument is not a valid
> > MySQL result resource in *
> > C:\Inetpub\wwwroot\WorkOrderSystem\ViewWorkOrder.php* on line *57*
> >
> > *Warning*: mysql_num_rows(): supplied argument is not a valid MySQL
> result
> > resource in *C:\Inetpub\wwwroot\WorkOrderSystem\ViewWorkOrder.php* on
> line *
> > 65
> >
> >
> > Code:
> > line 57: $row = mysql_fetch_object ($result);
> > line 65: if (mysql_num_rows($result) == 0) {
> > ?>
> > *
>
> STFW as Google has the answer..
>
> But... you need to actually provide MORE of the code, since the error
> pretty much tells you that you don't have a connection to your database.
>  Not a PHP issue really.
>
> Wolf
>

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