On Mon, 2008-11-03 at 15:56 +0100, Anders Norrbring wrote: > > Anders Norrbring wrote: > > > > > I've been staring myself blind, so now I don't get anywhere, please > > do > > > advice.. > > > > > > I have a web page printed with PHP, in a table I need to display > > > images that are stored in a SQL DB. > > > Getting the images into variables isn't an issue at all, but how do I > > > output it? > > > This is what I want to accomplish: > > > > > > <tr><td>Current image:</td><td> - THE IMAGE HERE - </td></tr> > > > > > > Starting to pull my hair.. > > > Anders. > > > > <img src="fetchimg?id=<nnnnn>"/> > > > > fetchimg.php: > > > > header('Content-Type: image/jpeg'); > > $img=<fetch from db>; > > print $img; > > > True Per, but I would prefer one single file in this case.. > > Anders. > > You can have the image script as part of the same PHP file, by checking to see if it is being called for an image rather than a normal page, but it just makes things more convoluted. Also, the base64 method will not work in IE. I had a similar problem at work that could only be solved by using a separate script to output the image. It can't be streamed inline in a consistent manner. Ash www.ashleysheridan.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php