You have: <?php echo substr($_SERVER['AUTH_USER'], 13); ?> and how do you want to get something? The subscring is displayed after the 13th character and if the AUTH_USER is shorter... Also you have: if (!$connect_id = ifx_connect("$database@$host", $user, $pass)) { // THE ACTUAL CONNECTION echo "Unable to connect to Informix Database\n"; // DISPLAY IF CONNECTION FAILS exit(); } and do you have tried: $connect_id = ifx_connect("$database@$host", $user, $pass)) || die("Unable to connect to Informix Database."); IF $user is the same as $_SERVER[AUTH_USER] and it is empty, you not connect since ifx_connect() exits befor it is started since you need all parameters. So you have to use: $connect_id = ifx_connect("$database@$host", "$user", "$pass")) || die("Unable to connect to Informix Database."); which pass at least TWO empty $user and $pass strings to the functions. Thanks, Greetings and nice Day/Evening Michelle Konzack Systemadministrator 24V Electronic Engineer Tamay Dogan Network Debian GNU/Linux Consultant -- Linux-User #280138 with the Linux Counter, http://counter.li.org/ ##################### Debian GNU/Linux Consultant ##################### Michelle Konzack Apt. 917 ICQ #328449886 +49/177/9351947 50, rue de Soultz MSN LinuxMichi +33/6/61925193 67100 Strasbourg/France IRC #Debian (irc.icq.com)
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