Re: PHP querying mysql db for data limited to the last month

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Sorry, I took that stuff out because it was making the page not load and so I figured it was wrong. I guess I should have posted the whole thing, but since it didn't work I left it out.

Micah, thank you very much for the idea, it is working great!!!


"Micah Gersten" <micah@xxxxxxxxxxx> wrote in message news:4897B67A.7050404@xxxxxxxxxxxxxx
1.  To get last months date, you can use strtotime("1 month ago")
instead of mktime.
2.  I don't see anywhere in the code where you are limiting by date.
Try using > and <.  Between is tricky on dates.

Thank you,
Micah Gersten
onShore Networks
Internal Developer
http://www.onshore.com



Vinny Gullotta wrote:
So I have this code I'm working with (pasted below) that queries a
mysql db table called timetracking. The goal of the page is to search
the db for all data based on a certain engineer, sorted by product and
it takes pre-defined values based on actions performed, sums them
based on product and display's the percentage of time an engineer has
spent on each product. Everything works great except I need to limit
the results to the last months data only, but everything I try seems
to just break it. Can anyone push me in the right direction a little?
I have tried using BETWEEN in the SELECT statement, some while
statements and if statements, and all I do is keep breaking it. If
anyone has any ideas, it would be exceptionally helpful.

Thanks in advance,
Vinny


<?php
$total = 0;
$today = date('Y-m-d h:i:s');
$monthago = date("Y-m-d h:i:s", mktime(date("h"), date("i"),
date("s"), date("m")-1, date("d"),   date("Y")));
echo "Today = ", $today;
echo "<br>One Month Ago = ", $monthago, "<br>";

$query = "SELECT *, SUM(timespent) FROM timetracking WHERE engineer =
'$engineer' GROUP BY product";
$result = mysql_query($query) or die(mysql_error());
$result2 = mysql_query($query) or die(mysql_error());
echo "<center>";

 while($row = mysql_fetch_array($result)){
  $total = $row['SUM(timespent)'] + $total;
 }
 while($row = mysql_fetch_array($result2)){
  $perc = $row['SUM(timespent)'] * 100 / $total;
  echo "[ <font color=#1E429B size=+1>", $row[product]. " = ".
number_format($perc,2), "%</font> ]";
 }

?>




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