is it possible because you can assign $func = foo and call $func() and it
will call foo(), maybe that its creating an endless loop of assigning the
function to itself?
On Sun, Aug 3, 2008 at 11:17 AM, brian <php@xxxxxxx> wrote:
> Waynn Lue wrote:
>
>> I've been running the script below:
>>
>> <?php
>> $appIds = getLotsOfAppIds();
>> foreach ($appIds as $appId) {
>> echo "$appId\n";
>> //echo memory_get_usage() . "\n";
>> try {
>> $getBundles = getBundles($appId);
>> $numBundles = count($registeredBundles);
>> echo $numBundles . "\n";
>> continue;
>> }
>> }
>> ?>
>>
>> And I get PHP Fatal Error: Allowed Memory Size Exhausted after it runs for
>> a
>> bit. Looking at the memory usage, it's because $getBundles (an array) is
>> huge, and keeps growing. What I'm confused by is why setting it to
>> something else in the next iteration of the foreach loop doesn't free the
>> previously allocated array, since there shouldn't be any more references
>> to
>> it. I've worked around it by explicitly calling unset($getBundles), but
>> just wanted to understand why it's working the way it does.
>>
>>
> Aside from on the 1st iteration, each time getBundles() is called, it
> creates an array within its own scope. Until PHP assigns the returned array
> to $getBundles, there are two in memory. Maybe that's the problem.
>
> I don't know how you can stand naming structures or variables the same as
> functions, btw. That would drive me nuts. Where is this $registeredBundles
> coming from? Perhaps you meant:
>
> $registeredBundles = getBundles($appId);
>
> b
>
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