Problem with using array_diff and array_combine

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I hope I can explain what I am trying to do.

I have two tables the first one has the custom form elements


formelements_id formelements_field_type formelements_field_caption members_id
35 	text 	test 	8
36 	text 	test2 	8


The second one has the customer id and the field value withe the field
name



dbelements_field_name 	dbelements_field_value 	members_id 	customer_id
35 	Test This Field 	8 	346
36 	                        8 	346
36 	 Test2 	                8 	347


If you look at the second table you will see that one field name is
related to two different  customers
and one field name on relates to one customer.

I am trying to look at these two tables and find customer that do not
have a row for each field name.
I have been trying with
array_combine($dbelements_field_array,$dbelements_id_array)
and also
array_diff($customf_array,$dbelements_field_array)

This are the tables  I /am using to create the arrays

/$contactsql = "SELECT * FROM contacts WHERE members_id = '8'";
$contact_result = |mysql_query|($contactsql);
while($contact_row=mysql_fetch_array($contact_result)){
$contactid_array[] = $contact_row['id'];
}
$sql1 = "SELECT * FROM dbelements WHERE members_id = '8'";
$sql_result1 = |mysql_query|($sql1);
while($row1=mysql_fetch_array($sql_result1)){
$dbelements_field_array[]=$row1["customer_id"];
$dbelements_field_array[].=$row1["dbelements_field_name"];
}

$sql2 = "SELECT * FROM customformelements WHERE members_id = '8'";
$sql_result2 =  |mysql_query|($sql2);
while($row2=mysql_fetch_array($sql_result2)){
$customf_array[]=$row2["formelements_id"];
}

Could somebody get me going in the right directions




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