Re: syntax error

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On Mon, Jul 21, 2008 at 7:55 AM, Aschwin Wesselius
<aschwin@xxxxxxxxxxxxxx> wrote:
> Eric Butera wrote:
>
> On Mon, Jul 21, 2008 at 7:24 AM, Ronald Wiplinger <tm.ronald@xxxxxxxxx>
> wrote:
>
>
> On a system with php4 and mysql 4.x I had these lines:
>
> require("../db-config");     // includes $dbhost, $buname, $dbpass
> $db = mysql_connect($dbhost, $dbuname, $dbpass);
> mysql_select_db($dbname,$db);
>
>    $sql = "SELECT * FROM CATEGORY WHERE .....";
>    $result = mysql_query($sql,$db);
>    $num=mysql_num_rows($result);
>    while ($myrow = mysql_fetch_array($result)) {
> ....
>
> Moving the *.php to a php5 and mysql 5.x site I get these errors:
>
> PHP Warning:  mysql_num_rows(): supplied argument is not a valid MySQL
> result resource in ...
> PHP Warning:  mysql_fetch_array(): supplied argument is not a valid MySQL
> result resource in ...
>
>
> Looking at the manual, I cannot see what I am doing wrong.
>
> bye
>
> R.
>
>
>
> Your mysql_connect is probably failing.  Look at your error log or
> look at mysql_error() for a reason why.
>
> Probably the mysql extension is not found or not loaded (due to not being
> compiled with the right path or the default path in PHP is not the right
> one). Happened to me a couple of times.....
>
>
> --
>
> Aschwin Wesselius
>
> 'What you would like to be done to you, do that to the other....'
>

Wouldn't that be  call to undefined function then?

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