Re: Need help with regular expression

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Your description of the problem is confusing.

Do you simply want to delete a table row if it contains a variable, e.g., $var='bigfoto' and append "==REPLACEMENT==" ? Where $var can be anything you assign.


Maxim Antonov wrote:
Hello.

But I need no td and tr inside regular expression
It is a part of my templater.


In real code it looks like:
  if(strlen($item[$key])<1){
return preg_replace('#\{%%%.*?\{%'.$key.'%\}.*?%%%\}#is','',$tpl);
            }

if one of $key inside {%%% .... %%%} points to empty array item - all section between {%%% %%%} must be deleted.



Daniel Brown :
On Wed, Jul 9, 2008 at 5:21 AM, Maxim Antonov <max@xxxxxxxxxxxxxxx> wrote:
Hi, all!

I try to use folowing regular expression:
$out =
preg_replace('#\{%%%.*?\{%bigfoto%\}.*?%%%\}#is','==REPLACEMENT==',$str);

[snip!]
I need result as:

<tr><td>NAME:</td><td><input type="text" name="name" value=""
size="80"/></td></tr>
<tr><td>Foto:</td><td><input type="file" name="foto" value="{%foto%}" />
 {%%%<br/><img alt="{%name%}" src="{%foto%}"/>%%%}
 </td></tr>
==REPLACEMENT==
[snip!]

    To get it *exactly* as you've mentioned here, use this instead:

<?php
$out = preg_replace('/<tr><td>Big.*\{%%%.*\{%bigfoto%\}.*%%%\}.*<\/tr>/Uis','==REPLACEMENT==',$str);
?>


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