Re: Question before I end up writing alot of extra code...

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Hey,

Dude you could use it this way

<input type='checkbox' name='something' value='1'>
<input type='checkbox' name='something' value='2'>
<input type='checkbox' name='something' value='3'>

Once u submit it,

do a small server side validation

if(isset($_POST['something'] || $_POST['something']) != ""){
insert...............
}

This way you could avoid replacing the values with nulls.

Thanks,
Vam

On Mon, Jul 7, 2008 at 12:25 PM, Jason Pruim <japruim@xxxxxxxxxx> wrote:

> Hi everyone!
>
> So it's been a nice long weekend, I come in to work and try and mess with a
> project that I'm working on to get some new features added. All was going
> well until I realized that now my application is breaking...
>
> Here's the details...
>
> PHP 5.2
> MySQL 5.2
>
> I store the info in the database which is submitted from a HTML form.. Some
> of it text boxes, some check boxes, some radio buttons... I $_POST the info
> from the form into the processing script.
>
> The problem I'm running into though, is when a value has not changed it
> doesn't get $_POSTed back and my update script erases the info in the
> database... I'm trying to avoid using $_GET since it can be quite a few
> variables.
>
> Is there anyway I can do it without comparing the original field to what I
> am displaying?
>
>
> --
>
> Jason Pruim
> Raoset Inc.
> Technology Manager
> MQC Specialist
> 11287 James St
> Holland, MI 49424
> www.raoset.com
> japruim@xxxxxxxxxx
>
>
>
>
>
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