Re: Return an Array and immediately reference an index

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On Sat, Apr 12, 2008 at 9:35 AM, Nathan Nobbe <quickshiftin@xxxxxxxxx> wrote:
>
> On Sat, Apr 12, 2008 at 12:18 PM, Casey <heavyccasey@xxxxxxxxx> wrote:
>
>
> >
> >
> >
> > On Sat, Apr 12, 2008 at 9:12 AM, Nathan Nobbe <quickshiftin@xxxxxxxxx>
> wrote:
> > > On Fri, Apr 11, 2008 at 6:33 PM, Daniel Kolbo <kolb0057@xxxxxxx> wrote:
> > >
> > >  search the archives ;)
> > >
> > >  http://www.mail-archive.com/php-general@xxxxxxxxxxxxx/msg224626.html
> > >
> > >  -nathan
> > <?php
> > function ReturnArray() {
> >    return array('a' => 'f', 'b' => 'g', 'c' => 'h', 'd' => 'i', 'e' =>
> 'j');
> > }
> >
> > echo ${!${!1}=ReturnArray()}['a']; // 'f'
> > ?>
>
> ya; i never did sit down and try to figure out how that works; care to
> explain ?
>
> -nathan
>

<?php
echo ${!${!1}=ReturnArray()}['a'];

${!${!1}=ReturnArray()}['a']
 !1 resolves to false.
${!${false}=ReturnArray()}['a']
 false resolves to... I don't know. Let's just say false resolves to "a".
${!$a=ReturnArray()}['a']
 $a is now the array. The ! changes the returned array into the
boolean false (like: if (!$handle = fopen('x', 'r')) { echo
'connection failed' }.
${false}['a']
 I don't know what false resolves to, but we're using "a".
$a['a']
?>
-- 
-Casey

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