Bojan Tesanovic wrote:
On Apr 12, 2008, at 12:33 AM, Daniel Kolbo wrote:
Hello,
I want to return an array from function and reference an index all in
one line. Is this possible?
In the code below I want I want $yo to be the array(5,6).
Here is what I've tried,
function returnarray() {
return array('lose' => array(5,6), 'win' => array(9,8));
}
$yo = returnarray()['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' => array(5,6), 'win' => array(9,8));
}
$yo = {returnarray()}['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' => array(5,6), 'win' => array(9,8));
}
$yo = ${returnarray()}['lose'];
var_dump($yo);
This gives notices as the result of returnarray() is being converted
to a string. $yo === NULL...not what i want.
function returnarray() {
return array('lose' => array(5,6), 'win' => array(9,8));
}
$yo = returnarray()->['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' => array(5,6), 'win' => array(9,8));
}
$yo = ${returnarray()}->['lose'];
var_dump($yo);
This yields a parse error.
Thanks for your help in advance.
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This is not possible in PHP, though you can have a Array wrapper class
function returnarray() {
return new ArrayObject( array('lose' => array(5,6), 'win' =>
array(9,8)) );
}
var_dump (returnarray()->offsetGet('lose'));
or even better make you own wrapper class with __set() and __get()
methods so you can have
var_dump (returnarray()->lose);
of course only in PHP5
Well, not quite so fast saying this is only possible in PHP5
You could do something like this.
<?php
function returnHash() {
return (object) array('lose' => array(5,6), 'win' => array(9,8));
}
print_r(returnHash()->lose);
?>
Basically, this converts your newly built array into an object, using
the stdClass object.
Then reference the index via an object variable name instead of an array
style access method.
Bojan Tesanovic
http://www.carster.us/
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