Re: How to determine which column "matched"

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On Fri, 2008-04-11 at 23:42 -0400, Robert Cummings wrote:
> On Fri, 2008-04-11 at 20:25 -0700, Rob Gould wrote:
> > I'm trying to figure out a way that SQL can pass a flag to PHP to say which column "matched" during a query.  
> > 
> > Let's say for instance that I want to search for the word "apple" in both column "producer", and column "designation".  I was hoping I could do something like this:
> > 
> > 
> > Select producer, flag=1 from wine
> > where producer like '%apple%'
> > UNION
> > Select designation, flag=2 from wine
> > where designation like '%apple%'
> 
> <?php
> 
> $query =
>     "SELECT "
>    ."    producer, "
>    ."    (producer like '%apple%') AS producerMatched "
     ."FROM "
     ."    wine "
>    ."WHERE "
>    ."    producer like '%apple%' "
>    ."UNION SELECT "
>    ."    designation, "
>    ."    (designation like '%apple%') AS designationMatched "
     ."FROM "
     ."    wine "
>    ."WHERE "
>    ."    designation like '%apple%' ";

Sorry, forgot the FROM clause. BTW, you shouldn't use a union, this can
be cleaned up to the following query:

<?php

    $query =
        "SELECT "
       ."    producer, "
       ."    (producer like '%apple%') AS producerMatched, "
       ."    designation, "
       ."    (designation like '%apple%') AS designationMatched "
       ."FROM "
       ."    wine "
       ."WHERE "
       ."    producer like '%apple%' "
       ."    OR "
       ."    designation like '%apple%' ";

?>

Cheers,
Rob.
-- 
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