Top-posting side comment: It's not nice to hijack threads.
My comments are below...
On Apr 11, 2008, at 5:33 PM, Daniel Kolbo wrote:
Hello,
I want to return an array from function and reference an index all
in one line. Is this possible?
In the code below I want I want $yo to be the array(5,6).
Here is what I've tried,
function returnarray() {
return array('lose' => array(5,6), 'win' => array(9,8));
}
$yo = returnarray()['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' => array(5,6), 'win' => array(9,8));
}
$yo = {returnarray()}['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' => array(5,6), 'win' => array(9,8));
}
$yo = ${returnarray()}['lose'];
var_dump($yo);
This gives notices as the result of returnarray() is being converted
to a string. $yo === NULL...not what i want.
function returnarray() {
return array('lose' => array(5,6), 'win' => array(9,8));
}
$yo = returnarray()->['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' => array(5,6), 'win' => array(9,8));
}
$yo = ${returnarray()}->['lose'];
var_dump($yo);
This yields a parse error.
Thanks for your help in advance.
Perhaps these pages may assist you:
http://php.net/manual/en/function.array.php
http://php.net/functions
For more immediate help, I think you want to do something along these
lines:
<?php
function returnArray ($index) {
$arr = array('lose'=>array(5,6), 'win'=>array(9,8));
return isset ($arr[$index]) ? $arr[$index] : 'Index not found';
}
$returnTheValueForThis = 'lose';
$result = returnArray ($returnTheValueForThis);
var_dump ($result);
?>
This var_dump will return:
array(2) { [0]=> int(5) [1]=> int(6) }
Hope that helps. Do some more reading in the manual to help yourself
out. ;)
~Philip
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