Dan I made a solution as below.
$time1 = strtotime("$sqldata[CaldTime]");
$time2 = strtotime("$sqldata[CallEnd]");
$interval = $time2 - $time1;
$TLength = date("i:s", strtotime("2008-01-01 01:00:$interval"));
Result 01:45
Works perfect for me. Do you agree or disagree dan?
On Mon, Apr 7, 2008 at 11:42 AM, <admin@xxxxxxxxxxxxxxxxxxx> wrote:
> I am having a date time comparison issue.
> I have statically set the values here. But the data is fed from the
database, CaldTime is timestamp and since it will not allow me to have 2
timestamps in the same table I set the CallEnd varchar(12). Storing the data
they seem to be the same for output. I checked hexadecimal and binary to look
for obscurities.
>
>
> $sqldata['CaldTime'] = "2008-04-07 11:15:32";
> $sqldata['CallEnd'] = "2008-04-07 11:17:17";
>
> $time1 = strtotime("$sqldata[CaldTime]");
> $time2 = strtotime("$sqldata[CallEnd]");
> $interval = $time2 - $time1;
>
> echo $interval;
>
> +++++++++++++++++++++++++++++++++++++++++++++++++++++++
> Displays like 1.75:0
> I am looking for a more precise time like 1:45 instead.
> Am I looking at this all wrong for time difference?
>
> Richard L. Buskirk
> Sorry my murloc got pawned in AV, and ever since I cant think right!
>
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>
This could be simplified to a function, but using some basic math....
<?php
$sqldata['CaldTime'] = "2008-04-07 11:15:32";
$sqldata['CallEnd'] = "2008-04-07 11:17:17";
$converted = explode('.',((strtotime($sqldata['CallEnd']) -
strtotime($sqldata['CaldTime'])) / 60));
$converted[1] = (($converted[1] / 6) * 3.6);
echo implode(':',$converted)."\n";
?>
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</Daniel P. Brown>
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