Re: PHP and #if

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On Mar 14, 2008, at 3:15 PM, Eric Gorr wrote:


On Mar 14, 2008, at 3:10 PM, Stut wrote:

On 14 Mar 2008, at 19:03, Eric Gorr wrote:
Unfortunately, such things cannot be used to wrap functions.

Erm, yes they can. Try it.

<?php
  if (rand(0,1) == 0)
  {
      function arse()
      {
          echo "arse 1\n";
      }
  }
  else
  {
      function arse()
      {
          echo "arse 2\n";
      }
  }

  arse();
?>


Gives:

Parse error: syntax error, unexpected T_STRING in /Users/Eric/Sites/ ifWrapping.php on line 3

Oh, sorry, apparently there are some invisible characters in the text you pasted which I had to zap first. Yes, this does work as expected.

However, try wrapping the arse function in a class.

<?php
class TestClass
{
	if ( rand(0,1) == 0 )
	{
		function arse()
		{
			echo "arse 1\n";
		}
	}
	else
	{
		function arse()
		{
			echo "arse 2\n";
		}
	}

}

$myVar = new TestClass;

$myVar->arse();
?>


That fails with:


Parse error: syntax error, unexpected T_IF, expecting T_FUNCTION in / Users/Eric/Sites/ifWrapping.php on line 4



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